abc+cca=1ab2, C언어 소스

abc+cca=1ab2, C언어 소스

abc cca=1ab2.c

//   abc

//+ cca

//  ------

//  1ab2

 

#include <stdio.h>

 

int main(void)

{

    int a = 0;

    int b = 0;

    int c = 0;

    int num1, num2, num3;

 

    printf("=== abc + cca = 1ab2를 만족하는 a,b,c 목록 ===\n");

    for (a = 1; a <= 9; a++)

    {

        for (b = 1; b <= 9; b++)

        {

            for (c = 1; c <= 9; c++)

            {

                num1 = a * 100 + b * 10 + c;//abc

                num2 = c * 100 + c * 10 + a;//cca

                num3 = 1000 + a * 100 + b * 10 + 2;//1ab2

 

                if (num1 + num2 == num3)

                {

                    printf("%d,%d,%d\n", a, b, c);

                }

            }

        }

    }

    return 0;

}